Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • S is any point on side QR of a PQR. Show that: PQ + QR + RP > 2 PS.

S is any point on side QR of a \trianglePQR. Show that:PQ + QR + RP > 2 PS.

Answers (1)

Given, \trianglePQR, S is any point on QR.

To prove: PQ + QR + RP > 2PS

Proof:-  we know that sum of two sides of a triangle is greater than the third side.

In \trianglePQS,

 PQ + QS > PS

and in \trianglePSR,

PR + SR > PS

On adding above both,

PQ + QS + SR + PR > PS + PS

\because QS + SR = QR

\Rightarrow PQ + QR + PR > 2PS

Hence proved.

Posted by

infoexpert24

View full answer

Similar Questions

Latest Question