Q is a point on the side SR of a DPSR such that PQ = PR. Prove that PS > PQ.
Given: Q is point on side SR in DPSR and PQ = PR
To Prove = PS > PQ
Proof: We know that exterior angle of any triangle is greater than each of the opposite interior angles
PQR is exterior angle of PSQ
PQR > PSQ
PQ = PR (Given)
PQR = PRQ (Angles opposite to equal sides are equal)
Then, PRQ = PRS
PRS > PSR
Now, side opposite to greater angle is longer in a triangle
Then PS > PR
PS > PQ ( PQ = PR)
Hence Proved.