Get Answers to all your Questions

header-bg qa

Q is a point on the side SR of a DPSR such that PQ = PR. Prove that PS > PQ.

Answers (1)

Given: Q is point on side SR in DPSR and PQ = PR

To Prove = PS > PQ

Proof: We know that exterior angle of any triangle is greater than each of the opposite interior angles

\therefore \anglePQR is exterior angle of \trianglePSQ

\therefore \anglePQR > \anglePSQ

\because PQ = PR                               (Given)

\anglePQR = \anglePRQ                       (Angles opposite to equal sides are equal)

Then, \anglePRQ = \anglePRS

\therefore \anglePRS > PSR

Now, side opposite to greater angle is longer in a triangle

Then PS > PR

PS > PQ (\because PQ = PR)

Hence Proved.

Posted by

infoexpert24

View full answer