Get Answers to all your Questions

header-bg qa

Show that in a quadrilateral ABCD, AB + BC + CD + DA > AC + BD

Answers (1)

Given, ABCD is a quadrilateral

To Prove :    AB + BC + CD + DA > AC + BD

Proof -  Since, we know that sum of the two sides of a triangle is greater than the third side.

In \triangleABC, AB + BC > AC

In \triangleBCD, BC + CD > BD

In \triangleCAD, AD + CD > AC

In \triangleBAD, BA + AD > BD

Adding all the above equations,

2(AB + BC + CA + AD) > 2(AC + BD)

\Rightarrow 2(AB + BC + CA + AD) > 2(AC + BD)

\Rightarrow AB + BC + CA + AD > AC + BD

Hence, proved.

Posted by

infoexpert24

View full answer