Describe hybridization in the case of PCl_{5} and SF_{6}. The axial bonds are longer as compared to equatorial bonds in PCl_{5} whereas in SF_{6} both axial bonds and equatorial bonds have the same bond length. Explain.

Answers (1)

The hybridization of the S in SF_{6} is sp^{3}d^{2} and the hybridization of the P in PCl_{5} is sp^{3}d.

We know that PCl_{5} has trigonal bipyramidal geometry. As such, the axial bonds are slightly longer as compared to the equatorial bonds. This is a result of the axial bonds experiencing greater repulsion from other bonds as compared to the equatorial bonds.

We know that SF_{6} has an octahedral structure. As such, all the bonds possess the same length this is because all bonds experience similar repulsion from other bonds.

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