q4) Divide as directed  

iv)

20 ( y+4 ) ( y^2 + 5 y + 3 ) \div 5 (y +4 )

Answers (1)

We have,
               \frac{20(y+4)(y^{2}+5y+3)}{5(y+4)} =\frac{4 \times 5(y+4)(y^{2}+5y+3)}{5(y+4)} = 4(y^{2}+5y+3)

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