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  • Draw a line segment of length 7 cm. Find a point P on it which divides it in the ratio 3 ratio 5.

Q: Draw a line segment of length 7 cm. Find a point P on it which divides it in the ratio 3:5.

Answers (1)

Solution
Given: AB = 7cm
The required ratio is 3:5
Let m = 3, n = 5
m+n= 3+5= 8

Steps of construction
  1.   Draw a line segment AB = 7cm.
  2.   Draw a ray AX making an acute angle with AB 
  3.   Locate 8 points A_{1},A_{2},A_{3}\cdots A_{8}  on AX on equidistant.         (Because m+n= 8 )
  4.   Join BA_{8} 
  5.   Through the point A_{3}  draw a line parallel to BA_{8} which intersects line AB at P..
  Here triangle AA3P is similar to triangle AA_{8}B
  AA_{3}/AA_{8}= AP/AB= 3/5        (by construction)
Therefore AP:BP= 3:5

 

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