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  • To draw a pair of tangents to a circle which are inclined to each other at an Angle of 60(degree)it is required to draw tangents at end points of those two radii of The circle the angle between them should be A135(degre) B90(degre) C60(degree) D120(degr)

To draw a pair of tangents to a circle which are inclined to each other at an Angle of 60^{\circ}, it is required to draw tangents at end points of those two radii of The circle, the angle between them should be

(A) 135^{\circ}                      (B) 90^{\circ}                        (C) 60^{\circ}                      (D) 120^{\circ}

Answers (1)

Answer(D) 120°
Solution
According to question:-

Given :\angle QPR= 60^{\circ}
Let       \angle QOR= x
 As we know that angle between tangent and radius of a circle is 90

\angle PQO= \angle PRO= 90^{\circ}
 We know that \angle PQO+ \angle PRO+ \angle QPR+\angle QOR= 360^{\circ}  

                                                       [\because sum of interior angles of quadrilateral is 360^{\circ} ]

90^{\circ}+90^{\circ}+x+60^{\circ}= 360^{\circ}|
240+x= 360^{\circ}
x= 120^{\circ}

 

Posted by

infoexpert27

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