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Draw a triangle ABC in which BC = 6 cm, CA = 5 cm and AB = 4 cm.Construct a triangle similar to it and of scale factor \frac{5}{3}

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Solution 
Given :  BC = 6cm, CA = 5cm, AB = 4cm
Scale factor = 5/3
Let m = 5 and n = 3

Steps of construction

  1. Draw line BC = 6cm
  2. Taking B and C as centre mark arcs of length 4cm and 5cm respectively which intersecting each other at point A.
  3. Join BA and CA
  4. Draw a ray BX making acute angle with BC.
  5. Locate 5 Points on BX in equidistant as B1, B2, B3, B4, B5.
  6. Join B3 to C and draw a line through B5 parallel to B3C to intersect at BC extended at  {C}'.

       7. Draw a line through  {C}' parallel to AC intersect AB extended at {A}' .

Now  {A}'B{C}'  is required triangle.

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