# Draw a triangle ABC in which BC = 6 cm, CA = 5 cm and AB = 4 cm.Construct a triangle similar to it and of scale factor $\frac{5}{3}$

Solution
Given :  BC = 6cm, CA = 5cm, AB = 4cm
Scale factor = 5/3
Let m = 5 and n = 3

Steps of construction

1. Draw line BC = 6cm
2. Taking B and C as centre mark arcs of length 4cm and 5cm respectively which intersecting each other at point A.
3. Join BA and CA
4. Draw a ray BX making acute angle with BC.
5. Locate 5 Points on BX in equidistant as B1, B2, B3, B4, B5.
6. Join B3 to C and draw a line through B5 parallel to B3C to intersect at BC extended at  ${C}'$.

7. Draw a line through  ${C}'$ parallel to AC intersect AB extended at ${A}'$ .

Now  ${A}'B{C}'$  is required triangle.

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