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  • Explain quantitatively the order of magnitude difference between the diamagnetic susceptibility of N_2 5X 10^ 9 (at STP) and Cu 10^ 5

Explain quantitatively the order of magnitude difference between the diamagnetic susceptibility of N_{2}(5 \times 10^{-9}) (at STP) and Cu ( 10^{-5})


 

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\rho_ N=\frac{28g}{22.4L}=\frac{28}{22400}gcm^{-3}
\rho _{Cu}=8gcm^{-3}
\rho _{N}\rho_{Cu}=\frac{28}{22400\times 8}=1.6\times 10^{-4}
\frac{x_N}{x_{Cu}}=\frac{5\times 10^{-9}}{10^{-5}}=5\times 10^{-4}
x=\frac{\text{Intensity of Magnetisation(M)}}{\text{Magnetising field Intensity (H)}}=\frac{\frac{\text{Magnetic moment( m)}}{\text{Volume(V)}}}{}H=\frac{m}{HV}
V=m'\rho
x=m\rho Hm'
x\propto \rho
\frac{x_{N}}{x_{Cu}}=\frac{\rho _N}{ \rho _ {Cu}}=1.6\times 10^{-4}

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