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Factorise : 

ii) 22y-32z

Answers (1)

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We have, 
               22y=  2 \times 11 \times y
                33z = 3 \times 11 \times z
So, we have   11 common in both 
Therefore,   

22y - 33z = 11(2y - 3z)

Posted by

Gautam harsolia

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