Find the total surface area of the following cuboids (Fig 11.31):
(i) Total surface area $ = 2(\mathrm{~h} \times \mathrm{l}+\mathrm{b} \times \mathrm{h}+\mathrm{b} \times \mathrm{l})=2(\mathrm{lb}+\mathrm{bh}+\mathrm{hl})$
$=2(6 \times 4+4 \times 2+6 \times 2)=2(24+8+12)$
$=2(24+8+12)=88 \mathrm{~cm}^2$
(ii) Total surface area $ = 2(\mathrm{~h} \times \mathrm{l}+\mathrm{b} \times \mathrm{h}+\mathrm{b} \times \mathrm{l})=2(\mathrm{lb}+\mathrm{bh}+\mathrm{hl})$
$=2(4 \times 4+4 \times 10+10 \times 4)=2(16+40+40)$
$=2(96)=192 \mathrm{~cm}^2$