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Find the total surface area of the following cuboids (Fig 11.31):

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(i)  Total surface area $ = 2(\mathrm{~h} \times \mathrm{l}+\mathrm{b} \times \mathrm{h}+\mathrm{b} \times \mathrm{l})=2(\mathrm{lb}+\mathrm{bh}+\mathrm{hl})$

$=2(6 \times 4+4 \times 2+6 \times 2)=2(24+8+12)$

$=2(24+8+12)=88 \mathrm{~cm}^2$

(ii) Total surface area $ = 2(\mathrm{~h} \times \mathrm{l}+\mathrm{b} \times \mathrm{h}+\mathrm{b} \times \mathrm{l})=2(\mathrm{lb}+\mathrm{bh}+\mathrm{hl})$

$=2(4 \times 4+4 \times 10+10 \times 4)=2(16+40+40)$

$=2(96)=192 \mathrm{~cm}^2$

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Devendra Khairwa

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