Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Following are four different relations about displacement, velocity, and acceleration for the motion of a particle in general. Choose the incorrect one(s) :

Following are four different relations about displacement, velocity, and acceleration for the motion of a particle in general. Choose the incorrect one(s) :

(a) V_{av}=\frac{1}{2}\left [ V(t_{1})+V(t_{2}) \right ]

(b) V_{av}=\frac{r(t_{2})-r(t_{1})}{t_{2}-t_{1}}

(c) r=\frac{1}{2}\left ( V(t_{2})-V(t_{1}) \right )\left ( t_{2}-t_{1} \right )

(d) a_{av}=\frac{V(t_{2})-V(t_{1})}{t_{2}-t_{1}}

Answers (1)

The answer is the option (a) and (c)

Explanation:

Option a:

The given relation is correct when the acceleration is uniform

Option c:

\vec{r}=\frac{1}{2}\left ( \vec{v}(t_{2})-\vec{v}(t_{1}) \right )\div \left ( t_{2}-t_{1} \right )

This is the relationship given in the question, but it is not possible as the LHS and RHS dimensions \left [ M^{0}L^{1}T^{0} \right ] and \left [ M^{0}L^{1}T^{2} \right ]do not match and hence the relationship cannot be considered valid.

 

Posted by

infoexpert24

View full answer

Similar Questions

Latest Question