Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • The horizontal range of a projectile fired at an angle of 15^{o} is 50 m. If it is fired with the same speed at an angle of 45^{o}, its range will be a) 60 m b) 71 m c) 100 m d) 141 m

The horizontal range of a projectile fired at an angle of 15^{o} is 50 m. If it is fired with the same speed at an angle of 45^{o}, its range will be

a) 60 m

b) 71 m

c) 100 m

d) 141 m

Answers (1)

The answer is the option (c)  100 m

Explanation:

According to the formula: 

R=\frac{u^{2}\sin {2\theta }}{g}

Given in the question:

\theta =15,R=50\; m

Putting in the formula we get:

u^{2}=100\; g

For \theta =45,

The value of the range is:

R=\frac{100\; g\times \sin{90}}{g}=100\; m

Posted by

infoexpert24

View full answer

Similar Questions

Latest Question