Identical springs of steel and copper are equally stretched. On which, more work will have to be to done?

Answers (1)

\frac{\Delta L_{1}}{\Delta L_{2}} =\frac{Ycu}{Ys}

Work done (WD) = F. \Delta L

WD steel/ WD copper = Y cu/ Ys

Ycu/Ys < 1, so WD steel < WD copper

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