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  • In Fig. 10.7, if angle DAB = 60 degree , angle ABD = 50 degree, then angle ACB is equal to: Fig. 10.7 (A) 60 degree (B) 50 degree (C) 70 degree (D) 80 degree

In Fig. 10.7, if \angle DAB = 60 ^{\circ}, \angle ABD = 50^{\circ}, then \angle ACB is equal to:

Fig. 10.7

(A) 60º

(B) 50º

(C) 70º

(D) 80º

Answers (1)

In \triangle ABD,

\angle ABD + \angle ADB +\angle DAB = 180^{\circ}

(Angle sum property of triangle)


\\50^o+ < ADB + 60^o = 180^o\\\Rightarrow \angle ADB = 70^o

Now, \angle ACB = \angle ADB = 70^{\circ}          

(Angles in the same segment are equal)
\angle ADB = 70^{\circ} \\ \angle ACB = 70^{\circ}

Posted by

infoexpert24

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