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  • In one dimensional motion, instantaneous speed v satisfies 0 \leq v < v_{0} . (a) The displacement in time T must always take non-negative values. (b) The displacement x in time T satisfies – v_{0}T < x < v_{0}T .

In one dimensional motion, instantaneous speed v satisfies 0 \leq v < v_{0} .
(a) The displacement in time T must always take non-negative values.
(b) The displacement x in time T satisfies – v_{0}T < x < v_{0}T .
(c) The acceleration is always a non-negative number.
(d) The motion has no turning points.

Answers (1)

The correct answer is the option (b) The displacement x in time T satisfies -v_{0}T < x < v_{0}T .

Explanation: The magnitude & direction of max. & min. velocity can be used to determine the max. & min. displacement.

v0 is the maximum velocity in the positive direction as well as in the opposite direction (or we can say minimum velocity).

Thus, v0T is the maximum displacement in the positive direction & -v0T is the maximum displacement in the opposite direction.

Thus, - v_{0}T < x < v_{0}T .

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