3 Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

Answers (1)

 BC = 48 m, CD = 17 m and AD = 40 m,

Length of the fence of a trapezium shaped field ABCD = 120 m = AB+BC+CD+DA

                                                                                                120=AB+48+17+40

                                                                                                AB=15m

Area of trapezium =

\frac{1}{2}\times sum \, of\, parallel\, sides\times height

=\frac{1}{2}\times (40+48)\times 15

=\frac{1}{2}\times (88)\times 15

= (44)\times 15

=660m^{2}

 

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