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M is a point on side BC of a triangle ABC such that AM is the bisector of \angleBAC. Is it true to say that perimeter of the triangle is greater than 2AM ? Give reason for your answer.

Answers (1)

True

Solution.        

Perimeter of \triangleABC =  AB + BC + AC

In \triangleAMB and \triangleAMC

We know that sum of two sides of a triangle is greater than third side.

AB + BM > AM ......(1)

and AC + MC > AM ......(2)

By adding (1) and (2) equation

AB + BM + MC + AC > 2AM

Since,  BC = BM + MC

 \thereforeAB + BC + AC > 2AM

=> Perimeter of \triangleABC > 2AM

Hence the given statement is true.

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