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  • Measure of two quantities along with the precision of respective measuring instrument is A=2.5\; m/s\pm 0.5\; m/s B= 0.10\; s\; \pm 0.01\;s

Measure of two quantities along with the precision of respective measuring instrument is

A=2.5\; m/s\pm 0.5\; m/s

B= 0.10\; s\; \pm 0.01\;s

The value of AB will be

a) (0.25 \pm 0.08) \; m

b) (0.25 \pm 0.5) m

c) (0.25 \pm 0.05) m

d) (0.25 \pm 0.135) m

Answers (1)

The answer is the option (a) (0.25\pm 0.08)m

Explanation : By using the given values of A & B,

X=AB=2.5\times 0.10=0.25\; m

\frac{\Delta x}{x}=\frac{\Delta A}{A}+\frac{\Delta B}{B}

=\frac{0.5}{2.5}+\frac{0.01}{0.10}

=\frac{0.075}{0.25}

Thus, \Delta x=0.075\cong 0.08

Thus, AB=(0.25\pm 0.08)m

Posted by

infoexpert22

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