# Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals :i) (a) $n=3,\; l=2,\; m_{l}=-2,m_{s}=-\frac{1}{2}$   (b)$n=3,\; l=2,\; m_{l}=-1,m_{s}=-\frac{1}{2}$ii) (a) $n=3,\; l=1,\; m_{l}=1,m_{s}=+\frac{1}{2}$     (b) $n=3,\; l=2,\; m_{l}=1,m_{s}=+\frac{1}{2}$iii) (a) $n=4,\; l=1,\; m_{l}=1,m_{s}=+\frac{1}{2}$     (b) $n=3,\; l=2,\; m_{l}=1,m_{s}=+\frac{1}{2}$iv) (a) $n=3,\; l=2,\; m_{l}=+2,m_{s}=-\frac{1}{2}$      (b) $n=3,\; l=2,\; m_{l}=+2,m_{s}=+\frac{1}{2}$

The answers are the options (i) and (iv) because the degenerate orbitals have the same n and l values. Herein, the other two options have different values of n and l; therefore they cannot possess similar energy.

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