Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • sqroot 2 power 2equals :- (A) 2 power minus 1by 6 (B) 2–6 (C) 2 power 1 by 6 (D)26

\sqrt[4]{\sqrt[3]{2^{2}}} equals :-
(A) 2^{-\frac{1}{6}}
(B)2-6
(C) 2^{\frac{1}{6}}
(D) 2^{6}

Answers (1)

Answer.     [C]
Solution.        
We have, \sqrt[4]{\sqrt[3]{2^{2}}}   =\left ( \left ( 2^{2} \right )^{}\frac{1}{3} \right )^{\frac{1}{4}}         

\because \sqrt[n]{a}= \left ( a \right )^{\frac{1}{n}}
\because \left ( a^{m} \right )^{n}= a^{m\times n}
So we get,
\left ( 2 \right )^{2\times \frac{1}{3}\times \frac{1}{4}}
= \left ( 2 \right )^{\frac{1}{3}\times \frac{1}{2}}
= \left ( 2 \right )^{\frac{1}{6}} 

Hence option C is correct.

Posted by

infoexpert27

View full answer

Similar Questions

Latest Question