The Balmer series in the hydrogen spectrum corresponds to the transition from n1 = 2 to n2= 3, 4. This series lies in the visible region. Calculate the wave number of line associated with the transition in Balmer series when the electron moves to n= 4 orbit. (RH= 109677 cm–1).

Answers (1)

Here n1 = 2, n= 4

^{-}v=109677\left ( \frac{1}{2^{2}}-\frac{1}{4^{2}} \right )

for n= 2, n= 4 transition in Balmer series.

=109667\left ( \frac{1}{4}-\frac{1}{16}\right )

=20564.44\; cm^{-1}

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