Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • The displacement time graph of a particle executing S.H.M. is shown in Figure. Which of the following statement is/are true?

The displacement time graph of a particle executing S.H.M. is shown in Figure. Which of the following statements is/are true?

(a) The force is zero at t = \left (\frac{3T}{4} \right )
(b) The acceleration is maximum at t = \left (\frac{4T}{4} \right )
(c) The velocity is maximum at t = \left (\frac{T}{4} \right )
(d) The P.E. is equal to the K.E. of oscillation at t = \left (\frac{T}{2} \right )

Answers (1)

Let us see the given options we get that,

(a) The particle is at its mean position t = \left (\frac{3T}{4} \right ), so the force acting on it is zero, but due to the inertia of mass the motion continues

a = 0 thus, F = 0.

(b) Particle velocity changes increasing to decrease so maximum at the change in velocity, at t = \left (\frac{4T}{4} \right ). Thus, acceleration is maximum here.

(c) The velocity is maximum at its mean position  t = \left (\frac{T}{4} \right ) as there is no retarding force on it.

(d) K.E. = 0 at t = \frac{T}{2} = \frac{2T}{4}.

So, the Potential Energy is not equal to kinetic energy.

Hence, the correct answer is the option (a),(b) and (c).

Posted by

infoexpert24

View full answer

Similar Questions

Latest Question