# The energy of $\sigma 2p_{z}$ molecular orbital is greater than $\pi 2p_{x}$ and $\pi 2p_{y}$ molecular orbitals in nitrogen molecule. Write the complete sequence of energy levels in the increasing order of energy in the molecule. Compare the relative stability and the magnetic behaviour of the following species :$N_{2},N_{2}^{+},N_{2}^{-},N{_{2}}^{2+}$

We know that the general sequence of the energy level of the molecular orbital can be written as,

We are also aware that, Bond order = ½ [electrons in BMO – electrons in ABMO]

In case of $N_{2}=10-\frac{4}{2}=3$

Hence, the bond order for

Hence, the bond order for

Hence, the bond order for

Therefore, we can conclude that the order of stability is:

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