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The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly
a) 1.2 nm  (b) 1.2 x 10-3 nm
(c) 1.2 x 10-6  nm (d). 1.2 x 10 nm

Answers (1)

The answer is the option (b)

Energy of the photon should be equal to the binding energy of the proton 

So, the energy of photon=

 1MeV=10^{6}\ast 1.6\ast 10^{-19}\\ \lambda=\frac{hc}{E}=6.63 \ast 10^{-34} \ast 3 \ast\frac{10^{8}}{1.6 \ast 10^{-13}}\\ =1.24 \ast 10^{-3}nm

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