The Young’s modulus for steel is more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?

Answers (1)

Y = stress/strain and Y \propto stress

Y (steel)/ Y(rubber) = Stress(steel)/Stress(rubber)

We know that Y steel > Y rubber

Y steel/Y rubber > 1

Hence, stress (steel)/stress (rubber) > 1

So, stress (steel) > stress (rubber)

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