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 Three photodiodes D1, D2, and D3 are made of semiconductors having band gaps of 2.5eV, 2eV, and 3eV, respectively. Which ones will be able to detect light of wavelength A^{\circ}?

Answers (1)

Explanation:-

According to the problem, the wavelength given 

Wavelength of light \lambda = 6000 A^{\circ}-6000\times 10^{10}m

now, 

using the Energy of light proton

E=\frac{h_{c}}{\lambda}=\frac{6.62\times10^{-34}\times3 \times 10^{8}}{6000\times10^{10}\times1.6\times10^{19}}eV=2.06eV

The energy of light is 2.06V

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