To construct a triangle similar to a given with its sides of the corresponding sides of , first draw a ray BX such that CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B1, B2, B3, ... on BX at equal distances and next step is to join
(A) B10 to C (B) B3 to C (C) B7 to C (D) B4 to C
Answer(C) B7 to C
Solution Given: is an acute angle.
Steps of construction
1. Draw any ray BX making angle with BC on the side opposite to vertex A.
2. Locate 7 points on BX in equidistant
3. Now join B7 to C
4. Draw a line through B3 parallel to B7C .