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  • To construct a triangle similar to a given tran ABC with its sides 3 by 7 of the corresponding sides of ABC first draw a ray BX such that angle CBX is an acute angle and X lies on the opposite side of A with respect to BCThen locate points B(1)B(2)B(3) on

3. To construct a triangle similar to a given $\triangle A B C$ with its sides of 3/7 the corresponding sides $\triangle A B C$, first, draw a ray BX such that $C B X$ is an acute angle and $X$ lies on the opposite side of $A$ with respect to $B C$. Then locate points $B_1, B_2, B_3, \ldots$ on $B X$ at equal distances and the next step is to join

(A) B10 to C                (B) B3 to C                  (C) B7 to C                  (D) B4 to C

Answers (1)

Answer(C) B7 to C
Solution Given: $\angle CBX$ is an acute angle.

In order to construct a triangle similar to a given $\triangle A B C$ with its sides $3 / 7$ we have to divide $B C$ in the ratio $3: 7$
$B X$ should have 7 equidistant points on it as 7 is a greater number
Now we have to join $B_7$ to $C$.

Therefore, the next step is to join B7 to C.

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infoexpert27

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