To draw a pair of tangents to a circle which are inclined to each other at an Angle of $60^{\circ}$, it is required to draw tangents at the end points of those two radii of The circle, the angle between them should be
(A) $135^{\circ}$
(B) $90^{\circ}$
(C) $60^{\circ}$
(D) $120^{\circ}$
Answer(D) 120°
Solution
According to question:-
Given: $\angle Q P R=60^{\circ}$
Let $\angle Q O R=x$
As we know the angle between the tangent and radius of a circle is 90
$
\angle P Q O=\angle P R O=90^{\circ}
$
We know that $\angle P Q O+\angle P R O+\angle Q P R+\angle Q O R=360^{\circ}$
[ $\because$. the sum of interior angles of a quadrilateral is $360^{\circ}$ ]
$
\begin{aligned}
& 90^{\circ}+90^{\circ}+x+60^{\circ}=360^{\circ} \\
& 240+x=360^{\circ} \\
& x=120^{\circ}
\end{aligned}
$