# To construct a triangle similar to a given $\bigtriangleup ABC$ with its sides $\frac{8}{5}$ of the corresponding sides of $\bigtriangleup ABC$ draw a ray BX such that $\angle CBX$ is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is (A) 5                            (B) 8                            (C) 13                          (D) 3

Solution
To construct a triangle similar to a triangle, with its sides  $\frac{8}{5}$  of the corresponding sides of given triangle, the minimum number of points to be located at an equal distance is equal to the greater of 8 and 5 in  .$\frac{8}{5}$ Here $8> 5$
So, the minimum number of points to be located at equal distance on ray BX is 8.

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