To construct a triangle similar to a given \bigtriangleup ABC with its sides \frac{8}{5} of the corresponding sides of \bigtriangleup ABC draw a ray BX such that \angle CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is
(A) 5                            (B) 8                            (C) 13                          (D) 3

Answers (1)

Answer (B) 8                         
Solution
To construct a triangle similar to a triangle, with its sides  \frac{8}{5}  of the corresponding sides of given triangle, the minimum number of points to be located at an equal distance is equal to the greater of 8 and 5 in  .\frac{8}{5} Here 8> 5
So, the minimum number of points to be located at equal distance on ray BX is 8.

 

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