What is the effect of the following processes on the bond order in N_{2} and O_{2}?

(i) N_{2}\rightarrow N{_{2}}^{+}+e^{-}

(ii) O_{2}\rightarrow O{_{2}}^{+}+e^{-}

 

Answers (1)

(i) N_{2} possesses a total of 14 electrons. When one electron is donated, these electrons are removed from the Bonding molecular orbital. Therefore, the BO for N_{2}=3

(ii) O_{2} possesses a total of 16 electrons, out of which 8 electrons are in the molecular orbitals and 4 are in the antibonding molecular orbitals. Hence, the BO for O_{2}=2

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