Which of the following have identical bond order?
(i) CN^{-}
(ii) NO^{+}
(iii) O{_{2}}^{-}
(iv) O{_{2}}^{2-}

Answers (1)

The answer is the option (i)  CN^{-}and (ii) NO^{+}

Explanation: They have identical bond order because in both of the species number of electrons in Nb = number of electrons in Nab, i.e. 14. Whereas the number of electrons in O{_{2}}^{-} is 17 and in O{_{2}}^{2-}  is 18.

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