Which of the following order of energies of molecular orbitals of N_{2} is correct?

(i) (\pi 2py)<(\sigma 2pz)<(\pi ^{*}2px)\approx (\pi ^{*}2py)
(ii) (\pi 2py)>(\sigma 2pz)>(\pi ^{*}2px)\approx (\pi ^{*}2py)
(iii) (\pi 2py)<(\sigma 2pz)>(\pi ^{*}2px)\approx (\pi ^{*}2py)
(iv) (\pi 2py)>(\sigma 2pz)<(\pi ^{*}2px)\approx (\pi ^{*}2py)

Answers (1)

The answer is the option (i) (\pi 2py)<(\sigma 2pz)<(\pi ^{*}2px)\approx (\pi ^{*}2py)

Explanation: Molecules like B2, C2 & N2 have 1 to 3 electrons in p orbital energy of  \sigma 2p molecular orbital are greater than that of \pi2p_{x} \; and \; \pi 2p_{y} molecular orbitals.

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