q3) workout the following divisions  

iii)

10 y ( 6y +21 ) \div 5 ( 2y + 7 )

Answers (1)

We have,
             10y(6y + 21) = 2 \times y \times 5 \times 3(2y + 7)
Therefore,
                  \frac{10y(6y+21)}{5(2y+7)} = \frac{2 \times 5 \times y \times 3(2y+7)}{5(2y+7)} = 6y

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