Write True or False and justify your answer in each of the following: Two chords AB and CD of a circle are each at distances 4 cm from the centre. Then AB = CD.
Given,
AB & CD are chords of a circle and they are equidistant (4 cm) from the centre O.
To find whether AB = CD
As the two chords AB and CD are each at a distance of 4 cm from the centre, this distance will be perpendicular distance.
Hence OM AB & ON CD
OM = ON = 4 cm
OM bisects AB & ON bisects CD
i.e.,
OMA = OND = 90°
OA = OD (Both are radius)
AOM DON (RHS Congruence)
AM = DN (by CPCT)
2AM = 2DN (Multiplying both sides by 2)
AB = DC