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Explain solution for RD Sharma class 12 chapter Mean value theorem exercise 14.1 question 9 sub question (i) math

Answers (1)

Answer:

               f(-5)=f(5)

Hint:

               f is continuous in[-5,5]

Given:

               f:[-5,5]\rightarrow R is differentiable

 \therefore f is continuous in  [-5,5] of possible

Let         f(-5)=f(5)

Thus f satisfies all the conditions of Rolle’s Theorem

Therefore, there existsc \in(-5,5) such thatf^{\prime}(c)=0

But this contradicts the hypothesis thatf^{\prime}(x)does not vanish anywhere.

Hence f(-5)=f(5)

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