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  • Please solve RD Sharma class 12 chapter Mean value theorem exercise 14.1 question 8 sub question (i) maths textbook solution

Please solve RD Sharma class 12 chapter Mean value theorem exercise 14.1 question 8 sub question (i) maths textbook solution

Answers (1)

Answer:

 f(-2)=f(2),(0,0) is the point where tangent will be parallel.

Hint:

f^{\prime}(x)=2 x exist (-2,2 )

Given:

               y=x^{2}, x \in[-2,2]

Explanation:

               y=x^{2}, x \in[-2,2]

  1. Being polynomialf(x) is continuous for all x and hence continuous in[-2,2] .
  2. f^{\prime}(x)=2 x, which exist ( -2,2)

             \therefore f(x) is derivable in (-2,2 )

       3. 

             \\ f(-2)=(-2)^{2}=4\\\\ f(2)=(2)^{2}=4\\\\ \therefore f(-2)=f(2)

Therefore, the tangent is parallel to x-axis.

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