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Explain solution RD Sharma class 12 chapter 7 Solution of Simultaneous Linear Equation Exercise Fill in the blank Question 1 Maths Textbook Solution.

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Answer \rightarrow x=1, y=-1, z=0

Hint \rightarrow I A=A

Given

\rightarrow\left[\begin{array}{lll} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}\right]\left[\begin{array}{l} x \\ y \\ z \end{array}\right]=\left[\begin{array}{c} 1 \\ -1 \\ 0 \end{array}\right]

Explanation

     \rightarrow\left[\begin{array}{lll} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}\right]\left[\begin{array}{l} x \\ y \\ z \end{array}\right]=\left[\begin{array}{c} 1 \\ -1 \\ 0 \end{array}\right]

            \left[\begin{array}{c} x \times 1+0 \times y+0 \times z \\ 0 \times x+1 \times y+0 \times z \\ 0 \times x+0 \times y+1 \times z \end{array}\right]=\left[\begin{array}{c} 1 \\ -1 \\ 0 \end{array}\right]

            \left[\begin{array}{l} x \\ y \\ z \end{array}\right]=\left[\begin{array}{c} 1 \\ -1 \\ 0 \end{array}\right]

Comparing both sides we get  x=1,y=-1,z=0

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