Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma Class 12 Chapter 21 Differential Equation exercise 21.5 question 4 maths textbook solution.

Please solve RD Sharma Class 12 Chapter 21 Differential Equation exercise 21.5 question 4 maths textbook solution.

Answers (1)

Answer:  y=\tan^{-1}x+C

Hint: You have to integrate by applying integration of xn.

Given: (x^2+1)\frac{dy}{dx}=1

Solution:\frac{dy}{dx}=\frac{1}{(x^2+1)}

dy=\frac{1}{(x^2+1)}dx

Integrating both sides,

\begin{array}{ll} \int d y=\int \frac{1}{1+x^{2}} d x\; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \quad & {\left[\int \frac{1}{1+x^{2}} d x=\tan ^{-1} x+C\right]} \\\\ y=\tan ^{-1} x+C \end{array}

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Time Table 2025 Live: UP Board exams from February 24; CBSE, BSEB date sheet soon
anam-khan

CBSE Date Sheet 2025 Live: Class 10, 12 board exam dates soon; syllabus, sample papers
anam-khan

Extra time in CBSE exams for students with type 1 diabetes: Kerala SHRC seeks report on plea

Latest Question