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  • Please solve RD Sharma Class 12 Chapter 21 Differential Equation exercise 21.5 question 4 maths textbook solution.

Please solve RD Sharma Class 12 Chapter 21 Differential Equation exercise 21.5 question 4 maths textbook solution.

Answers (1)

Answer:  y=\tan^{-1}x+C

Hint: You have to integrate by applying integration of xn.

Given: (x^2+1)\frac{dy}{dx}=1

Solution:\frac{dy}{dx}=\frac{1}{(x^2+1)}

dy=\frac{1}{(x^2+1)}dx

Integrating both sides,

\begin{array}{ll} \int d y=\int \frac{1}{1+x^{2}} d x\; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \quad & {\left[\int \frac{1}{1+x^{2}} d x=\tan ^{-1} x+C\right]} \\\\ y=\tan ^{-1} x+C \end{array}

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