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  • Explain solution RD Sharma Class 12 Chapter 21 Differential Equation exercise 21.5 question 22 Maths.

Explain solution RD Sharma Class 12 Chapter 21 Differential Equation exercise 21.5 question 22 Maths.

Answers (1)

Answer: C=1

Hint: Find value of C.

Given: \sin\left ( \frac{dy}{dx} \right )=k

Solution: \sin\left ( \frac{dy}{dx} \right )=k,y=1

\begin{aligned} &\frac{d y}{d x}=\sin ^{-1} k \\ &\int d y=\int \sin ^{-1} k d x \\ &\Rightarrow y=x \sin ^{-1} k+C \\ &\Rightarrow 1=0+C \\ &\Rightarrow C=1 \end{aligned}

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