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  • Please solve RD Sharma class 12 chapter Mean Value Theoram exercise 14.2 question 6 maths textbook solution

Please solve RD Sharma class 12 chapter Mean Value Theoram exercise 14.2 question 6 maths textbook solution

Answers (1)

Answer:  \left(\frac{1}{2}, \frac{3}{4}\right)

Hint: You must know the slope of tangent’
 

Given:y=x^{2}+x parallel to chord: \left [ 0,0 \right ],\left [ 1,2 \right ]

Solution:

y=x^{2}+x,[0,0],[1,2]

\frac{d y}{d x}=2 x+1

Slope of tangent = 2x + 1

Slope of line joining [0, 0] and [1, 2] =  = 2

The tangent is parallel to this line:

\therefore Slope is equal

\begin{aligned} &2 x+1=2 \\ &2 x=2-1 \\ &2 x=1 \\ &x=\frac{1}{2} \end{aligned}

x=\frac{1}{2}

\therefore \quad y=\left(\frac{1}{2}\right)^{2}+\frac{1}{2}

            \begin{aligned} &=\left(\frac{1}{4}\right)+\frac{1}{2} \\ &=\frac{3}{4} \end{aligned}

Hence, the points are \left(\frac{1}{2}, \frac{3}{4}\right)

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