Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A ball is dropped from a height of 10 m. If the energy of the ball reduces by 40% after striking the ground, how much high can the ball bounce back? (g = 10 m s^–2)

A ball is dropped from a height of 10 m. If the energy of the ball reduces by 40\% after striking the ground, how much high can the ball bounce back? (g = 10 m s^{-2})

Answers (1)

Solution.
When the ball is dropped from 10 meters, the total energy will be in the form of potential energy.
Potential energy can be calculated as:
PE=mgh
After striking the ground, 40\% of energy is lost. Hence, it will have only 60\% of energy.
With the help of this 60\% energy, the object will attain maximum height.
Therefore, if height attained is H then we can say:

60\%(mg(10))=mgh

\Rightarrow \frac{60}{100}(mg(10))=mgh

\Rightarrow h=6m

The height attained is 6m.

Posted by

infoexpert26

View full answer

Similar Questions

Latest Question