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  • A girl having mass of 35 kg sits on a trolley of mass 5 kg. The trolley is given an initial velocity of 4 ms^–1 by applying a force. The trolley comes to rest after traversing a distance of 16 m.

A girl having mass of 35 kg sits on a trolley of mass 5 kg. The trolley is given an initial velocity of 4 ms^{-1} by applying a force.
The trolley comes to rest after traversing a distance of 16 m.

(a) How much work is done on the trolley?  

(b) How much work is done by the girl?

Answers (1)

Solution

Mass of the girl = 35 kg
Mass of the trolley = 5 kg
Initial velocity of trolley = 4m/s
Total distance travelled by trolley = 16 m
We know that

\\\;v^2-u^2 = 2as \\\; a=\frac{v^2-u^2}{2s} \\\; = \frac{-16}{2\times 16}= -0.5

Force=ma=40\times (-0.5) = -20N
         \\\;work\; done\; on\; the\; trolley\;=20N\times 16m=320 J.\\\; work \;done \;by \;the\; girl =0 J.

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