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A person of mass 60 kg wants to lose 5kg by going up and down a 10m high stairs. Assume he burns twice as much fat while going up than coming down. If 1 kg of fat is burnt on expending 7000 kilo calories, how many times must he go up and down to reduce his weight by 5 kg?

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The energy produced by 1 kg fat=7000 k cal

Energy produced by 5 kg fat=35000 k cal=35×106 cal

Energy consumed to go up one time=mgh

Energy consumed to go up and down one time=mgh+0.5mgh

E=\frac{3}{2}mgh=\frac{3}{2}\times 60\times 10\times 10=9000 J=\frac{9000}{4.2}cal

Let us assume that he goes up and down n times, then

n\times \frac{9000}{4.2}=35\times 10^{6}

n=35\times 10^{6}\times \frac{4.2}{9000}=16.3\times10^3

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