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If an average person jogs, he produces $14.5 \times 10^{3} cal/min.$ This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires $580 \times 10^{3} cal$ l for evaporation) is
(a) 0.025 kg
(b) 2.25 kg
(c) 0.05 kg
(d) 0.20 kg

Answers (1)

The answer is the option (a) 0.025 kg

$\text{Amount of sweat produced}=\frac{14.5\times10^3}{580\times10^3}=0.025Kg$

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infoexpert24

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