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A system goes from P to Q by two different paths in the P-V diagram as shown in Figure. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100 J. What is the heat exchanged by the system in path 2?

Answers (1)

For path 1 Q1=1000J

WD=W_1-W_2=100

W_1=WD through path 1

W_2=WD through path 2

W_{2}=W_{1}-100 (Change in internal energy by both paths are same)

\Delta U=Q_{1}-W_{1}=Q_{2}-W_{2}\\ 1000-W_{1}=Q_{2}-(W_1-100)

Q_2=900J

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