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An ideal gas undergoes isothermal process from some initial state I to final state f. Choose the correct alternatives

a) dU = 0

b) dQ = 0

c) dQ = dU

d) dQ = dW

Answers (1)

The answer is the option (a) and (d).

Since the process is isothermal \Delta T=0or T is constant 

 For an ideal gas, dU=Change in internal energy=nCvdT  

dT=0 ;Thus dU=0  

dQ=dU+dW 

 dQ=dW

Hence, a and d are correct.

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