Calculate the strength of 5 volume H_{2}O_{2} solution.

Answers (1)

5 volume H_{2}O_{2}solution signifies that 1 L of 5 volume H_{2}O_{2} when decomposed, gives 5L of O_2 at NTP.

H_{2}O_{2} \rightarrow 2H_{2}O + O_2

 

H_{2}O_{2}- 68g

2H_{2}O + O_2– 22.4l at NTP

 

22.4L of O_2 at NTP is gotten from H_{2}O_{2} is 68g

 

5L of O_2 at NTP is produced from H_{2}O_{2} = \frac{68}{22.4}\times5=15.18g

But 5L of O_2 at NTP is from 5 volume of 1L H_{2}O_{2}

 

Strength of H_{2}O_{2} in 5 volume H_{2}O_{2} = 15.18L

% strength of H_{2}O_{2} sol = \frac{15.18}{1000}\times100=1.518%

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