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Which of the following equations depict the oxidising nature of H_{2}O_{2}?

(i)2MnO_{4}^{-}+6H^{+}+5H_{2}O_{2}\rightarrow 2Mn^{2+}+8H_{2}O+5O_{2}

(ii)2Fe^{3+}+2H^{+}+H_2O_{2}\rightarrow 2Fe^{2+}+2H_{2}O+O_{2}

(iii)2I^{-}+2H^{+}+H_{2}O_{2}\rightarrow I_{2}+2H_{2}O

(iv)KIO_{4}+H_{2}O_{2}\rightarrow KIO_{3}+H_{2}O+O_{2}

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The answer is the option (iii)2I^{-}+2H^{+}+H_{2}O_{2}\rightarrow I_{2}+2H_{2}O

Iodine ions have a negative charge and are oxidised to form I_{2}. Therefore, H_{2}O_{2}  is the oxidizing agent.

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